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Post
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Published
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Mar 4, 2022
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C
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学习思考
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基本含义 


__builtin_return_address(0)返回当前函数的返回地址
__builtin_return_address(1)返回当前函数的调用函数的返回地址
__builtin_return_address(2)返回当前函数的调用函数的调用函数的返回地址
编译出来的实际效果



由此可见就是使用 FP 串联了整个函数调用堆栈,上述的 函数(__builtin_return_address) 也就是通过串联起来的 [FP,#0x4] 操作完成了对上一级 LR 的查找
由此可以可以配合 dobby 对函数hook并打印出 lr 调用链
int level=4; u_long lr0,lr1,lr2,lr3,lr4; [&]()->void { // 调用这个 registerLR 本身也会触发一次函数调用 会有一个lr,故从1开始 switch (level) { case 1: lr0 = reinterpret_cast<u_long>(__builtin_return_address(1)); LOGD("LR -> %p",(void*)(lr0-soAddr)); break; case 2: lr1 = reinterpret_cast<u_long>(__builtin_return_address(1)); lr0 = reinterpret_cast<u_long>(__builtin_return_address(2)); LOGD("LR -> %p %p",(void*)(lr0-soAddr),(void*)(lr1-soAddr)); break; case 3: lr2 = reinterpret_cast<u_long>(__builtin_return_address(1)); lr1 = reinterpret_cast<u_long>(__builtin_return_address(2)); lr0 = reinterpret_cast<u_long>(__builtin_return_address(3)); LOGD("LR -> %p %p %p",(void*)(lr0-soAddr),(void*)(lr1-soAddr),(void*)(lr2-soAddr)); break; case 4: lr3 = reinterpret_cast<u_long>(__builtin_return_address(1)); lr2 = reinterpret_cast<u_long>(__builtin_return_address(2)); lr1 = reinterpret_cast<u_long>(__builtin_return_address(3)); lr0 = reinterpret_cast<u_long>(__builtin_return_address(4)); LOGD("LR -> %p %p %p %p",(void*)(lr0-soAddr),(void*)(lr1-soAddr),(void*)(lr2-soAddr),(void*)(lr3-soAddr)); break; case 5: lr4 = reinterpret_cast<u_long>(__builtin_return_address(1)); lr3 = reinterpret_cast<u_long>(__builtin_return_address(2)); lr2 = reinterpret_cast<u_long>(__builtin_return_address(3)); lr1 = reinterpret_cast<u_long>(__builtin_return_address(4)); lr0 = reinterpret_cast<u_long>(__builtin_return_address(5)); LOGD("LR -> %p %p %p %p %p",(void*)(lr0-soAddr),(void*)(lr1-soAddr),(void*)(lr2-soAddr),(void*)(lr3-soAddr),(void*)(lr4-soAddr)); break; } }();
- 作者:axhlzy
- 链接:https://github.com/axhlzy/article/9bf98736-d310-4187-8e0f-91c4285e74a2
- 声明:本文采用 CC BY-NC-SA 4.0 许可协议,转载请注明出处。

